WebMar 29, 2024 · Given Sn = 4n – n2 Taking n = 1 S1 = 4 × 1−12 = 4 – 1 = 3 ∴ Sum of first term of AP is 3 Taking n = 2 in Sn S2 = 4×2−2^2 S2 = 8 – 4 S2 = 4 ∴ Sum of first 2 terms is 4 But … WebJan 27, 2024 · In an AP if Sn = n(4n + 1) then Find the AP. AboutPressCopyrightContact usCreatorsAdvertiseDevelopersTermsPrivacyPolicy & SafetyHow …
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WebSep 20, 2024 · Expert-Verified Answer 26 people found it helpful Wafabhatt given , Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 (2)-3 =13 so, AP is 5, 13 , 21 and so on Find Math textbook solutions? Class 7 Class 6 Class 5 Class 4 WebFeb 1, 2024 · The sum of the first n terms of an AP is given by Sn, = 3n^2 - 4n. Determine the AP and the 12th term. ← Prev Question Next Question → +3 votes 79.8k views asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) The sum of the first n terms of an AP is given by S n, = 3n 2 - 4n. Determine the AP and the 12 th term. arithmetic progression
WebNCERT Exemplar Class 10 Maths Exercise 5.3 Sample Problem 1. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, find the value of n. Summary: An arithmetic progression is a sequence where each term, except the first term, is obtained by adding a fixed number to its previous term. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, then the value ... WebThe sum of the first n term of an A.P. is given by S n=3n 2+2n. Determine the A.P. and its 15 th term. Medium Solution Verified by Toppr S n=3n 2+2n Taking n=1, we get S 1=3(1) 2+2(1) ⇒S 1=3+2 ⇒S 1=5 ⇒a 1=5 Taking n=2, we get S 2=3(2) 2+2(2) ⇒S 2=12+4 ⇒S 2=16 ∴a 2=S 2−S 1=16−5=11 Taking n=3, we get S 3=3(3) 2+2(3) ⇒S 3=27+6 ⇒S 3=33
WebJan 11, 2016 · IN an AP, if sn=n [4n+1] find the AP Asked by archita123 11 Jan, 2016, 06:12: PM Expert Answer Answered by 11 Jan, 2016, 06:22: PM Application Videos This … WebClass 10 Maths NCERT Solutions Chapter 5 Exercise 5.3 Question 11 . Summary: If the sum of the first n terms of an AP is 4n - n 2, then the first term is equal to 3, the sum of first two terms is equal to 4, the second term is equal to 1, and 3rd term, 10th term and the nth terms are equal to -1, -15, (5 - 2n) respectively.
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WebSolution We know that, the nth term of an AP is; an= Sn−Sn−1 an= n(4n+1)−(n−1){4(n−1)+1} [∵ Sn= n(4n+1)] ⇒ an =4n2+n−(n−1)(4n−3) ⇒ an =4n2+n−4n2+3n+4n−3 ⇒ an =8n−3 P … small head microcephalyWebSolution: The sum of n terms S n = 441 Similarly, S n-1 = 356 a = 13 d= n For an AP, S n = (n/2) [2a+ (n-1)d] Putting n = n-1 in above equation, l is the last term. It is also denoted by a n. The result obtained is: S n -S n-1 = a n So, 441-356 = a n a n = 85 = 13+ (n-1)d Since d=n, n (n-1) = 72 ⇒n 2 – n – 72= 0 Solving by factorization method, small head men in blackWebAug 26, 2024 · In an AP, if Sn = n (4n + 1), then find the AP. arithmetic progression class-10 1 Answer +1 vote answered Aug 26, 2024 by Sima02 (49.6k points) selected Aug 26, 2024 … small head medical conditionWebApr 10, 2024 · The Indian Navy has released the official notification 1400 vacancies for the Indian Navy SSR Agniveer Exam 2024. The selection process includes a Computer Based Test, Written Exam & Physical Fitness Test (PFT), and last stage of Medical Examination. Candidates applying for the exam must check the Indian Navy SSR Agniveer Eligibility … small head medical termWebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin … small head massagerWebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. song you remember whenWebDec 5, 2024 · The sum of the first n terms of an arithmetic progression (AP) is given by: Sn = n/2 [2a + (n-1)d] where a is the first term of the AP, d is the common difference, and n is the number of … song you never know